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Configuration = 114
cycles = (10 6 1 7 5)(9 4 2 8 3)

a = 1, b = 2, c = 8
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cycles = (10 5 7 2 9 3 1 6 4)(8)

a = 2, b = 4, c = 10
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cycles = (10)(9 1 4 2 7)(8 3 5)(6)

a = 3, b = 5, c = 8
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cycles = (10)(9 1 7 2 5)(8)(6)(4)(3)

a = 1, b = 7, c = 9
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cycles = (10)(9 4 7)(8)(6)(5)(3)(2)(1)